20x-5+3x^2+10=180

Solution for 20x-5+3x^2+10=180 equation:

20x-5+3x^2+10=180

We move all terms to the left:

20x-5+3x^2+10-(180)=0

We add all the numbers together, and all the variables

3x^2+20x-175=0

a = 3; b = 20; c = -175;
Δ = b2-4ac
Δ = 202-4·3·(-175)
Δ = 2500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2500}=50$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-50}{2*3}=\frac{-70}{6}
=-11+2/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+50}{2*3}=\frac{30}{6}
=5
$